I would like to know how to bind parameters to values within an expression tree
Something like
Expression<Func<String, String, bool>> e1 = (x,y) => x == y;
Then I would like to bind y, while preserving it as a single expression. A obvious attempt would be something like
Expresion<Func<String, bool>> e2 = x => e1(x, "Fixed Value Here");
But that would turn my expression into an Invoke node. Is there a way to simply bind a parameter within my first expression while getting the signature of the second expression?
Expression trees represent code in a tree-like data structure, where each node is an expression, for example, a method call or a binary operation such as x < y . You can compile and run code represented by expression trees.
Expression trees allow you to build code dynamically at runtime instead of statically typing it in the IDE and using a compiler. They are well explained in the documentation.
Expression Class (System. Provides the base class from which the classes that represent expression tree nodes are derived. It also contains static (Shared in Visual Basic) factory methods to create the various node types. This is an abstract class.
Expression<Func<String, String, bool>> e1 = (x,y) => x == y;
var swap = new ExpressionSubstitute(e1.Parameters[1],
Expression.Constant("Fixed Value Here"));
var lambda = Expression.Lambda<Func<string, bool>>(
swap.Visit(e1.Body), e1.Parameters[0]);
with
class ExpressionSubstitute : ExpressionVisitor
{
public readonly Expression from, to;
public ExpressionSubstitute(Expression from, Expression to)
{
this.from = from;
this.to = to;
}
public override Expression Visit(Expression node)
{
if (node == from) return to;
return base.Visit(node);
}
}
this uses ExpressionVisitor
to rebuild the expression, substituting y
with the constant.
Another approach is to use Expression.Invoke
, but this doesn't work in all cases.
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