I have a string of binary that I then convert to an integer using atoi()
. When I do this it seems to automatically convert the binary to decimal. The issue is that the resulting integer is negative and doesn't agree with any of the online binary-to-decimal converters. Is something broken with atoi()
? Should I be using a different function instead?
Code:
string myString = "01000101";
int x = atoi(myString.c_str());
cout << x;
Thanks
atoi
doesn't handle binary numbers, it just interprets them as big decimal numbers. Your problem is that it's too high and you get an integer overflow due to it being interpreted as decimal number.
The solution would be to use stoi
, stol
or stoll
that got added to string
in C++11. Call them like
int i = std::stoi("01000101", nullptr, 2);
int
value.std::string
you want to convert.size_t *
where it'll save the index of the first non digit character.int
that corresponds to the base that'll be used for conversion..For information on the functions look at its cppreference page.
Note that there are also pre C++11 functions with nearly the same name, as example: strtol
compared to the C++11 stol
.
They do work for different bases too, but they don't do the error handling in the same way (they especially lack when no conversion could be done on the given string at all e.g trying to convert "hello" to a string) and you should probably prefer the C++11 versions.
To make my point, passing "Hello" to both strtol
and the C++11 stol
would lead to:
strtol
returns 0
and doesn't give you any way to identify it as error,stol
from C++11 throws std::invalid_argument
and indicates that something is wrong.Falsely interpreting something like "Hello" as integers might lead to bugs and should be avoided in my opinion.
But for completeness sake a link to its cppreference page too.
It sounds like you should be using strtol()
with 2
as the last argument.
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