Bigquery: STRUCT (*) syntax

Question

How can I automatically apply STRUCT to all fields in a table without specifying them by name?

Example that does not work:

WITH data as (
 SELECT 'Alex' as name, 14 as age, 'something else 1' other_field
UNION ALL 
 SELECT 'Bert' as name, 14 as age, 'something else 2' other_field
UNION ALL 
 SELECT 'Chiara' as name, 13 as age, 'something else 3' other_field
)

SELECT AS STRUCT(SELECT * except (other_field) from data) as student_data

Returns: Error: Scalar subquery cannot have more than one column unless using SELECT AS STRUCT to build STRUCT values at [9:17]

This however works:

WITH data as (
 SELECT 'Alex' as name, 14 as age, 'something else 1' other_field
UNION ALL 
 SELECT 'Bert' as name, 14 as age, 'something else 2' other_field
UNION ALL 
 SELECT 'Chiara' as name, 13 as age, 'something else 3' other_field
)

SELECT STRUCT(name,age) as student_data

from data

The problem is that once I have 100 columns where only 5 don't belong, it makes me crazy to write them out. Is there a simpler way to use some version of Select * Except()?

Answer 1

Below for BigQuery Standard SQL

#standardSQL
WITH data AS (
  SELECT 'Alex' AS name, 14 AS age, 'something else 1' other_field UNION ALL 
  SELECT 'Bert' AS name, 14 AS age, 'something else 2' other_field UNION ALL 
  SELECT 'Chiara' AS name, 13 AS age, 'something else 3' other_field
)
SELECT (
  SELECT AS STRUCT * EXCEPT(other_field)
  FROM UNNEST([t])
  ) AS student_data
FROM data t   

with output

Row student_data.name   student_data.age     
1   Alex                14   
2   Bert                14   
3   Chiara              13