Better solution for this loop and return data ? Javascript [closed]

Question

convertType(arr) {
    let resultArr = arr.map(arr => {
      if (arr == '0') {
        return  'zero'
      }
      if (arr == '1') {
        return 'one'
      }
      if (arr == '2') {
        return   'two' 
      }
      if (arr == '3') {
        return  'three' 
      }
    })
    return resultArr;
  }

i need to find maybe a better solution for this loop and how to get these results back in a better way. Okay there is always a "switch" loop but what do you think about this? is it good?

This is work good , but i want better solution.

Answer 1

I'd make an array and look up indicies:

const numbers = ['zero', 'one', 'two', 'three'];

convertType(arr) {
  return arr.map(item => numbers[item]);
}

If the values being compared against aren't array indicies or might not have all values starting from 0, use an object:

const numbers = {
  2: 'two',
  3: 'three'
  somethingElse: 'something else'
};

with the same code for convertType.