Playing around with go, I threw together this code:
package main
import "fmt"
const N = 10
func main() {
ch := make(chan int, N)
done := make(chan bool)
for i := 0; i < N; i++ {
go (func(n int, ch chan int, done chan bool) {
for i := 0; i < N; i++ {
ch <- n*N + i
}
done <- true
})(i, ch, done)
}
numDone := 0
for numDone < N {
select {
case i := <-ch:
fmt.Println(i)
case <-done:
numDone++
}
}
for {
select {
case i := <-ch:
fmt.Println(i)
default:
return
}
}
}
Basically I have N channels doing some work and reporting it on the same channel -- I want to know when all the channels are done. So I have this other done
channel that each worker goroutine sends a message on (message doesn't matter), and this causes main to count that thread as done. When the count gets to N, we're actually done.
Is this "good" go? Is there a more go-idiomatic way of doing this?
edit: To clarify a bit, I'm doubtful because the done
channel seems to be doing a job that channel closing seems to be for, but of course I can't actually close the channel in any goroutine because all the routines share the same channel. So I'm using done
to simulate a channel that does some kind of "buffered closing".
edit2: Original code wasn't really working since sometimes the done
signal from a routine was read before the int it just put on ch
. Needs a "cleanup" loop.
Here is an idiomatic use of sync.WaitGroup for you to study
(playground link)
package main
import (
"fmt"
"sync"
)
const N = 10
func main() {
ch := make(chan int, N)
var wg sync.WaitGroup
for i := 0; i < N; i++ {
wg.Add(1)
go func(n int) {
defer wg.Done()
for i := 0; i < N; i++ {
ch <- n*N + i
}
}(i)
}
go func() {
wg.Wait()
close(ch)
}()
for i := range ch {
fmt.Println(i)
}
}
Note the use of closures in the two go routine definitions and note the second go
statement to wait for all the routines to finish, then close the channel, so range
can be used.
looks like you want a sync.WaitGroup
(http://golang.org/pkg/sync/#WaitGroup)
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