Best way to get distinct values from large table

Question

I have a db table with about 10 or so columns, two of which are month and year. The table has about 250k rows now, and we expect it to grow by about 100-150k records a month. A lot of queries involve the month and year column (ex, all records from march 2010), and so we frequently need to get the available month and year combinations (ie do we have records for april 2010?).

A coworker thinks that we should have a separate table from our main one that only contains the months and years we have data for. We only add records to our main table once a month, so it would just be a small update on the end of our scripts to add the new entry to this second table. This second table would be queried whenever we need to find the available month/year entries on the first table. This solution feels kludgy to me and a violation of DRY.

What do you think is the correct way of solving this problem? Is there a better way than having two tables?

Answer 1

Using a simple index on the columns required (Year and Month) should greatly improve either a DISTINCT, or GROUP BY Query.

I would not go with a secondary table as this adds extra over head to maintaining the secondary table (inserts/updates deletes will require that you validate the secondary table)

EDIT:

You might even want to consider using Improving Performance with SQL Server 2005 Indexed Views

Answer 2

Make sure to have an Clustered Index on those columns. and partition your table on these date columns an place the datafiles on different disk drives I Believe keeping your index fragmentation low is your best shot.

I also Believe having a physical view with the desired select is not a good idea, because it adds Insert/Update overhead. on average there's 3,5 insert's per minute. or about 17 seconds between each insert (on average please correct me if I'm wrong)

The question is are you selecting more often than every 17 seconds? That's the key thought. Hope it helped.