Behaviour of JVM during out of memory error? List s = new ArrayList<String>();

Question

try {
    for(;;) {
        s.add("Pradeep");
    }
} finally {
    System.out.println("In Finally");
}

In the try block the jvm runs out of memory,then how is jvm excuting finally block when it has no memory?

Output:

In Finally
Exception in thread "main" java.lang.OutOfMemoryError: Java heap space

Answer 1

Presumably the System.out.println call requires less memory than the s.add("Pradeep") call.

If s is an ArrayList for instance, the s.add call may cause the list to attempt to double up it's capacity. This is possibly a quite memory demanding operation, thus it is not very surprising that the JVM can continue executing even if it can't perform such relatively expensive task.