BeautifulSoup4: select elements where attributes are not equal to x

Question

I'd like to do something like this:

soup.find_all('td', attrs!={"class":"foo"})

I want to find all td that do not have the class of foo.
Obviously the above doesn't work, what does?

Answer 1

BeautifulSoup really makes the "soup" beautiful and easy to work with.

You can pass a function in the attribute value:

soup.find_all('td', class_=lambda x: x != 'foo')

Demo:

>>> from bs4 import BeautifulSoup
>>> data = """
... <tr>
...     <td>1</td>
...     <td class="foo">2</td>
...     <td class="bar">3</td>
... </tr>
... """
>>> soup = BeautifulSoup(data)
>>> for element in soup.find_all('td', class_=lambda x: x != 'foo'):
...     print element.text
... 
1
3

Answer 2

There is a method .select() which allows you to pass CSS selectors as a string:

soup.select('td:not(.foo)')

The above code will return all <td> tags which are not of the class foo.