beautifulsoup4 doesn't return content

Question

Hi, I followed and understood this article on how to read content from sites and it worked perfectly: geeksforgeeks.org:Reading selected webpage content using Python Web Scraping

But when I changed my code to work with another site it doesn't return any value. I am trying to get those Value1 and Value2 etc.. as shown below.

Please Note: It's Legal to read content from that web page.

import requests 
from bs4 import BeautifulSoup 

# the target we want to open     
url='https://hackerone.com/directory?offers_bounties=true&asset_type=URL&order_direction=DESC&order_field=started_accepting_at'

#open with GET method 
resp=requests.get(url) 

#http_respone 200 means OK status 
if resp.status_code==200: 
    print("Successfully opened the web page") 
    print("The news are as follow :-\n") 

    # we need a parser,Python built-in HTML parser is enough . 
    soup=BeautifulSoup(resp.text,'html.parser')     

    # l is the list which contains all the text i.e news  
    l=soup.find("tr","spec-directory-entry daisy-table__row fade fade--show") 

    #now we want to print only the text part of the anchor. 
    #find all the elements of a, i.e anchor 
    for i in l: 
        print(i.text) 
else: 
    print("Error") 

Here's the website source code:

<tr class="spec-directory-entry daisy-table__row fade fade--show">
    <a href="/livestream" class="daisy-link spec-profile-name">Value1</a>
<tr class="spec-directory-entry daisy-table__row fade fade--show">
    <a href="/livestream" class="daisy-link spec-profile-name">Value2</a>
<tr class="spec-directory-entry daisy-table__row fade fade--show">
.
.
.

Answer 1

JavaScript needed to render the webpage contents. Using prerenderio service is an easy/light way to get the data you're looking for from the page.

import requests 
from bs4 import BeautifulSoup 

# the target we want to open
# changed to use prerenderio service 
url='http://service.prerender.io/https://hackerone.com/directory?offers_bounties=true&asset_type=URL&order_direction=DESC&order_field=started_accepting_at'

#open with GET method 
resp=requests.get(url) 

#http_respone 200 means OK status 
if resp.status_code==200: 
    print("Successfully opened the web page") 
    print("The news are as follow :-\n") 

    # we need a parser,Python built-in HTML parser is enough . 
    soup=BeautifulSoup(resp.text,'html.parser')     

    # l is the list which contains all the text i.e news  
    l=soup.find("tr","spec-directory-entry daisy-table__row fade fade--show") 

    #now we want to print only the text part of the anchor. 
    #find all the elements of a, i.e anchor 
    for i in l: 
        print(i.text) 
else: 
    print("Error") 

The returned data from the above code:

Successfully opened the web page
The news are as follow :-

LivestreamManaged
04 / 2019
73
$100
$150-$250

---

Edited: Responding to Ahmad's comment

Here's the code to only get the values for "Livestream" table row.

import requests 
from bs4 import BeautifulSoup 

# the target we want to open
# changed to use prerenderio service 
url='http://service.prerender.io/https://hackerone.com/directory?offers_bounties=true&asset_type=URL&order_direction=DESC&order_field=started_accepting_at'

#open with GET method 
resp=requests.get(url) 

#http_respone 200 means OK status 
if resp.status_code==200: 
    print("Successfully opened the web page") 
    print("The news are as follow :-\n") 

    # we need a parser,Python built-in HTML parser is enough . 
    soup=BeautifulSoup(resp.text,'html.parser')     

    # l is the list which contains all "tr" tags  
    l=soup.findAll("tr","spec-directory-entry daisy-table__row fade fade--show")

    # looping through the list of table rows
    for i in l:
        # checking if the current row is for 'Livestream'
        if i.find('a').text == 'Livestream':
          # printing the row's values except the first "td" tag
          for e in i.findAll('td')[1:]:
            print(e.text)
else: 
    print("Error")

Result:

Successfully opened the web page
The news are as follow :-

04 / 2019
73
$100
$150-$250