Beautifulsoup - How to get all links inside a block with a certain class?

Question

I have the following HTML Dom:

    <div class="meta-info meta-info-wide"> <div class="title">Разработчик</div> <div class="content contains-text-link"> 

<a class="dev-link" href="http://www.jourist.com&amp;sa=D&amp;usg=AFQjCNHiC-nLYHAJwNnvDyYhyoeB6n8YKg" rel="nofollow" target="_blank">Перейти на веб-сайт</a>

 <a class="dev-link" href="mailto:[email protected]" rel="nofollow" target="_blank">Написать: [email protected]</a> 

 <div class="content physical-address">Diagonalstraße 41
    20537 Hamburg</div> </div> </div>

I need to get all links(url) with class dev-link inside block div.meta-info-wide.

I tried this obvious way, but does not work:

divTag = soup.find_all("div", {"class":"meta-info-wide"})
        print(len(divTag))

        for tag in divTag:
            tdTags = tag.find_all("a", {"class":"dev-link"})
            for tag in tdTags:
                print tag.text

Answer 1

Try the following:

import bs4

html = """    
<div class="meta-info meta-info-wide"> <div class="title">Разработчик</div> <div class="content contains-text-link"> 
<a class="dev-link" href="http://www.jourist.com&amp;sa=D&amp;usg=AFQjCNHiC-nLYHAJwNnvDyYhyoeB6n8YKg" rel="nofollow" target="_blank">Перейти на веб-сайт</a>
<a class="dev-link" href="mailto:[email protected]" rel="nofollow" target="_blank">Написать: [email protected]</a> 
<div class="content physical-address">Diagonalstraße 4120537 Hamburg</div> </div> </div>"""

soup = bs4.BeautifulSoup(html, "html.parser")

for div in soup.find_all("div", {"class":"meta-info-wide"}):
    for link in div.select("a.dev-link"):
        print link['href']

This gives you:

http://www.jourist.com&sa=D&usg=AFQjCNHiC-nLYHAJwNnvDyYhyoeB6n8YKg
mailto:[email protected] 

The select() is used to return all a tags which have the class dev-link. This is the recommended method to use when there are two or more CSS classes involved.

Tested with BeautifulSoup 4.5.1, Python 2.7.12