Bazel Build Multiple Targets at Once

Question

I want a Bazel rule that is able to build multiple targets at once. So basically something like this:

build_all(
  name = "build_all",
  targets = [
    "//services/service1:build",
    "//services/service2:build",
    "//services/service3:build",
  ]
)

So I would just run

bazel build //:build_all

to build all my services with one simple command (and the same for testing). But I couldn't find any current solutions.

Is there a way to achieve this?

Answer 1

It would appear that filegroup would be a ready made rule that could be abused for the purpose:

filegroup(
  name = "build_all",
  srcs = [
    "//services/service1:build",
    "//services/service2:build",
    "//services/service3:build",
  ]
)

It otherwise allows you to give a collective name to bunch of files (labels) to be passed conveniently along, but seems to work just as well as a summary target to use on the command line.

Answer 2

Because I was trying to deploy multiple Kubernetes configurations I ended up using Multi-Object Actions for rules_k8s which then looks like:

load("@io_bazel_rules_k8s//k8s:objects.bzl", "k8s_objects")

k8s_objects(
   name = "deployments",
   objects = [
      "//services/service1:build",
      "//services/service2:build",
      "//services/service3:build",
   ]
)