I have a batch script which will print the entire line of search string into a text file.
for %%i in (log.txt) do (
FINDSTR /G:pattern.txt %%i >> output.txt
)
Example:
pattern.txt contains search string ERROR
and below is the sample text in log.txt
2013-06-30 02:17:55,562 INFO Service started
2013-06-30 02:17:55,578 INFO Sending mail...
2013-06-30 02:17:55,578 DEBUG Element value: 1
2013-06-30 02:17:55,578 ERROR error occurred and message is ""
2013-06-30 02:17:55,578 DEBUG bit version: 8
2013-06-30 02:17:55,578 INFO Service stopped
The above batch script will print each line of text whenever it finds the string ERROR
in log.txt So, the output.txt will look have lines like below
2013-06-30 02:17:55,578 ERROR error occurred and message is ""
How can I print only previous and next lines of search string like below:
2013-06-30 02:17:55,578 DEBUG Element value: 1
2013-06-30 02:17:55,578 DEBUG bit version: 8
Thanks in advance.
@echo off
setlocal EnableDelayedExpansion
rem Assemble the list of line numbers
set numbers=
for /F "delims=:" %%a in ('findstr /I /N /C:"error occurred" log.txt') do (
set /A before=%%a-1, after=%%a+1
set "numbers=!numbers!!before!: !after!: "
)
rem Search for the lines
(for /F "tokens=1* delims=:" %%a in ('findstr /N "^" log.txt ^| findstr /B "%numbers%"') do echo %%b) > output.txt
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