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In a Windows XP .bat file, how do I set a variable value to use double quote? I couldn't find special characters for batch file.
SET myVariable= " \"myValue \" "
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Use double percent signs ( %% ) to carry out the for command within a batch file. Variables are case sensitive, and they must be represented with an alphabetical value such as %a, %b, or %c. ( <set> ) Required. Specifies one or more files, directories, or text strings, or a range of values on which to run the command.
Double quotes enable escaping through the use of the backslash (\). For example, if the special character semicolon is a value that is double-quoted, it should be represented as backslash semicolon (\;) so that the Integration Engine knows that the actual value (;) should be used.
When referencing a variable, it is generally advisable to enclose its name in double quotes. This prevents reinterpretation of all special characters within the quoted string -- except $, ` (backquote), and \ (escape).
inside double-quoted strings, use `" or "" to escape double-quotes. inside single-quoted strings, use '' to escape single-quotes.
You can use the method @Patrick Cuff has offered or you can do it quite simply:
SET var="Value"
Let's see if it works...
ECHO %var%
and the output is:
"Value"
Yes! :)
149
If this is for Windows, you need to escape the double quotes with a caret (^):
set myVariable=^"myVlaue^"
Putting single quotes around the value won't work, the value will include the single and double quotes.
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