Menu
I have a text file containing ~300k rows. Each row has a varying number of comma-delimited fields, the last of which is guaranteed numerical. I want to sort the file by this last numerical field. I can't do:
sort -t, -n -k 2 file.in > file.out as the number of fields in each row is not constant. I think sed, awk maybe the answer, but not sure how. E.g:
awk -F, '{print $NF}' file.in gives me the last column value, but how to use this to sort the file?
747
Sort allows us to sort a file by columns by using the -k option.
Without any flags, the sort command sorts the file contents in ascending order by default. To reverse the sorting order, add the -r flag to the sort command, like this: sort -r fruits. txt . Sorting in reverse order by adding the -r flag applies to other examples in this tutorial.
Use awk to put the numeric key up front. $NF is the last field of the current record. Sort. Use sed to remove the duplicate key.
awk -F, '{ print $NF, $0 }' yourfile | sort -n -k1 | sed 's/^[0-9][0-9]* //' 
vim file.in -c '%sort n /.*,\zs/' -c 'saveas file.out' -c 'q' If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
