Menu
I have the following file and I need to print everything except $1 and $2 by awk
File:
INFORMATION DATA 12 33 55 33 66 43
INFORMATION DATA 45 76 44 66 77 33
INFORMATION DATA 77 83 56 77 88 22
...
the desirable output:
12 33 55 33 66 43
45 76 44 66 77 33
77 83 56 77 88 22
...
838
The awk variables $1 or $2 through $nn represent the fields of each record and should not be confused with shell variables that use the same style of names. Inside an awk script $1 refers to field 1 of a record; $2 to field 2 of a record.
awk '{print $1}' information. txt prints the first column. Then the output of that command (which you saw earlier on) is piped, using the pipe symbol | , to the head command, where its -1 argument selects the first line of the column. If you wanted two lines printed, you'd do: awk '{print $1}' information.txt | head -2.
The “NF” AWK variable is used to print the number of fields in all the lines of any provided file. This built-in variable iterates through all the lines of the file one by one and prints the number of fields separately for each line.
Well, given your data, cut should be sufficient:
cut -d\ -f3- infile
Although it adds an extra space at the beginning of each line compared to yael's expected output, here is a shorter and simpler awk based solution than the previously suggested ones:
awk '{$1=$2=""; print}'
or even:
awk '{$1=$2=""}1'
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
