I have these two files
File1:
9 8 6 8 5 2
2 1 7 0 6 1
3 2 3 4 4 6
File2: (which has over 4 million lines)
MN 1 0
JK 2 0
AL 3 90
CA 4 83
MK 5 54
HI 6 490
I want to compare field 6 of file1, and compare field 2 of file 2. If they match, then put field 3 of file2 at the end of file1 I've looked at other solutions but I can't get it to work correctly.
Desired output:
9 8 6 8 5 2 0
2 1 7 0 6 1 0
3 2 3 4 4 6 490
My attempt:
awk 'NR==FNR{a[$2]=$2;next}a[$6]{print $0,a[$6]}' file2 file1
program just hangs after that.
To print all lines in file1 with match if available:
$ awk 'FNR==NR{a[$2]=$3;next;} {print $0,a[$6];}' file2 file1
9 8 6 8 5 2 0
2 1 7 0 6 1 0
3 2 3 4 4 6 490
To print only the lines that have a match:
$ awk 'NR==FNR{a[$2]=$3;next} $6 in a {print $0,a[$6]}' file2 file1
9 8 6 8 5 2 0
2 1 7 0 6 1 0
3 2 3 4 4 6 490
Note that I replaced a[$2]=$2
with a[$2]=$3
and changed the test a[$6]
(which is false if the value is zero) to $6 in a
.
Your own attempt basically has two bugs as seen in @John1024's answer:
a
, where you should be storing field 3 as the value (since you want to keep it for later), i.e., it should be a[$2] = $3
.a[$6]
is false when the value in a
is zero, even if it exists. The correct test is $6 in a
.Hence:
awk 'NR==FNR { a[$2]=$3; next } $6 in a {print $0, a[$6] }' file2 file1
However, there might be better approaches, but it is not clear from your specifications. For instance, you say that file2
has over 4 million lines, but it is unknown if there are also that many unique values for field 2. If yes, then a
will also have that many entries in memory. And, you don't specify how long file1
is, or if its order must be preserved for output, or if every line (even without matches in file2
) should be output.
If it is the case that file1
has many fewer lines than file2
has unique values for field 2, and only matching lines need to be output, and order does not need to be preserved, then you might wish to read file1
first…
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