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Avoiding implicit def ambiguity in Scala

I am trying to create an implicit conversion from any type (say, Int) to a String...

An implicit conversion to String means RichString methods (like reverse) are not available.

implicit def intToString(i: Int) = String.valueOf(i)
100.toCharArray  // => Array[Char] = Array(1, 0, 0)
100.reverse // => error: value reverse is not a member of Int
100.length // => 3

An implicit conversion to RichString means String methods (like toCharArray) are not available

implicit def intToRichString(i: Int) = new RichString(String.valueOf(i))
100.reverse // => "001"
100.toCharArray  // => error: value toCharArray is not a member of Int
100.length // => 3

Using both implicit conversions means duplicated methods (like length) are ambiguous.

implicit def intToString(i: Int) = String.valueOf(i)
implicit def intToRichString(i: Int) = new RichString(String.valueOf(i))
100.toCharArray  // => Array[Char] = Array(1, 0, 0)
100.reverse // => "001"
100.length // => both method intToString in object $iw of type 
   // (Int)java.lang.String and method intToRichString in object
   // $iw of type (Int)scala.runtime.RichString are possible 
   // conversion functions from Int to ?{val length: ?}

So, is it possible to implicitly convert to String and still support all String and RichString methods?

like image 388
Synesso Avatar asked Aug 27 '09 06:08

Synesso


4 Answers

I don't have a solution, but will comment that the reason RichString methods are not available after your intToString implicit is that Scala does not chain implicit calls (see 21.2 "Rules for implicits" in Programming in Scala).

If you introduce an intermediate String, Scala will make the implict converstion to a RichString (that implicit is defined in Predef.scala).

E.g.,

$ scala
Welcome to Scala version 2.7.5.final [...].
Type in expressions to have them evaluated.
Type :help for more information.

scala> implicit def intToString(i: Int) = String.valueOf(i)
intToString: (Int)java.lang.String

scala> val i = 100
i: Int = 100

scala> val s: String = i
s: String = 100

scala> s.reverse
res1: scala.runtime.RichString = 001
like image 194
Richard Dallaway Avatar answered Oct 18 '22 03:10

Richard Dallaway


As of Scala 2.8, this has been improved. As per this paper (§ Avoiding Ambiguities) :

Previously, the most specific overloaded method or implicit conversion would be chosen based solely on the method’s argument types. There was an additional clause which said that the most specific method could not be defined in a proper superclass of any of the other alternatives. This scheme has been replaced in Scala 2.8 by the following, more liberal one: When comparing two different applicable alternatives of an overloaded method or of an implicit, each method gets one point for having more specific arguments, and another point for being defined in a proper subclass. An alternative “wins” over another if it gets a greater number of points in these two comparisons. This means in particular that if alternatives have identical argument types, the one which is defined in a subclass wins.

See that other paper (§6.5) for an example.

like image 26
Francois G Avatar answered Oct 18 '22 04:10

Francois G


Either make a huge proxy class, or suck it up and require the client to disambiguate it:

100.asInstanceOf[String].length

like image 2
Mitch Blevins Avatar answered Oct 18 '22 04:10

Mitch Blevins


The only option I see is to create a new String Wrapper class MyString and let that call whatever method you want to be called in the ambiguous case. Then you could define implicit conversions to MyString and two implicit conversions from MyString to String and RichString, just in case you need to pass it to a library function.

like image 2
Kim Stebel Avatar answered Oct 18 '22 03:10

Kim Stebel