Avoid ggplot sorting the x-axis while plotting geom_bar()

Question

I have the following data which I want to plot with ggplot:

SC_LTSL_BM    16.8275
SC_STSL_BM    17.3914
proB_FrBC_FL   122.1580
preB_FrD_FL    18.5051
B_Fo_Sp    14.4693
B_GC_Sp    15.4986

What I want to do is to make a bar plot and maintain the order of the bar, (i.e. starting with SC_LTSL_BM ...B_GC_Sp). But the default behavior of ggplot geom_bar is to sort them. How can I avoid that?

  library(ggplot2)
  dat <- read.table("http://dpaste.com/1469904/plain/")
  pdf("~/Desktop/test.pdf")
  ggplot(dat,aes(x=V1,y=V2))+geom_bar()
  dev.off()

The current figure looks like this:

Answer 1

You need to tell ggplot that you've got an ordered factor already, so it doesn't automatically order it for you.

dat <- read.table(text=
"SC_LTSL_BM    16.8275
SC_STSL_BM    17.3914
proB_FrBC_FL   122.1580
preB_FrD_FL    18.5051
B_Fo_Sp    14.4693
B_GC_Sp    15.4986", header = FALSE, stringsAsFactors = FALSE)

# make V1 an ordered factor
dat$V1 <- factor(dat$V1, levels = dat$V1)

# plot
library(ggplot2)
ggplot(dat,aes(x=V1,y=V2))+geom_bar(stat="identity")

Answer 2

Here is an approach that does not modify the original data, but uses scale_x_discrete. From ?scale_x_discrete, "Use limits to adjust the which levels (and in what order) are displayed". For example:

dat <- read.table(text=
                "SC_LTSL_BM    16.8275
              SC_STSL_BM    17.3914
              proB_FrBC_FL   122.1580
              preB_FrD_FL    18.5051
              B_Fo_Sp    14.4693
              B_GC_Sp    15.4986", header = FALSE, stringsAsFactors = FALSE)
# plot
library(ggplot2)
ggplot(dat,aes(x=V1,y=V2))+
  geom_bar(stat="identity")+
  scale_x_discrete(limits=dat$V1)

Answer 3

dplyr lets you easily create a row column that you can reorder by in ggplot.

library(dplyr)
dat <- read.table("...") %>% mutate(row = row_number())
ggplot(df,aes(x=reorder(V1,row),y=V2))+geom_bar()

Answer 4

You can also just re-order the corresponding factor as described here

x$name <- factor(x$name, levels = x$name[order(x$val)])