Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Automatically resolve Interface<T> to Implementation<T> in StructureMap (differ only by generic type T)

Tags:

I have an interface (IRepository<T>) that is currently being extended for each specific repository, ie: IUserRepository : IRepository<User>.

Each of these interfaces has corresponding concrete classes, ie: UserRepository : Repository<User>, IUserRepository.

These individual repositories don't add any additional functionality, they are all empty interfaces/classes that are used simply to pass the generics around.

I use StructureMap to resolve IUserRepository into UserRepository using a Registry with an assembly scanner and some naming conventions.

I'd like this to move to a way more optimised state, where instead of passing around instances of IUserRepository and getting it resolved to UserRepository, I can pass around IRepository<User> and have it resolved to Repository<User>.

This would remove the need to create these extra empty interfaces and classes.

I can't work out a way to use StructureMap's configuration to setup this generic mapping. Something like this:

For(typeof(IRepository<>).Use(typeof(Repository<>)).WithTheGenericTypeFromTheInterfaceSuppliedAsATypeParameter(); 

Edit

After getting the first couple of answers, I want to clarify this a bit more.

I don't want to create individual classes for the For bit of the configuration. I want to have the following classes/interfaces in my code:

  • IRepository<T> where T : Entity
  • Repository<T> : IRepository<T> where T : Entity
  • Person : Entity
  • Product : Entity
  • Order : Entity
  • Whatever : Entity

And have the following mappings achieved with convention:

IRepository<Person> => Repository<Person> IRepository<Product> => Repository<Product> IRepository<Order> => Repository<Order> IRepository<Whatever> => Repository<Whatever> 

But I do not want to have to create a mapping for each one, ala:

For<IRepository<Person>>().Use<Repository<Person>>(); For<IRepository<Product>>().Use<Repository<Product>>(); For<IRepository<Order>>().Use<Repository<Order>>(); For<IRepository<Whatever>>().Use<Repository<Whatever>>(); 

I want a single mapping that will work for any IRepository:

For<IRepository<>>().Use<Repository<>>().WithTheSameGenericType(); 

I would then use this to inject the repositories into services:

public MyService(IRepository<User> userRepository) 

And expect that to be resolved to a Repository<User> at runtime.

like image 880
Michael Shimmins Avatar asked Jan 25 '11 01:01

Michael Shimmins


2 Answers

Turns out there is no fancy method to call, or no fancy wiring to do, you just use For and Use (the non generic versions):

public class DataRegistry : Registry {     public DataRegistry()     {         For(typeof (IRepository<>)).Use(typeof(Repository<>));     } } 

When I inject a IRepository<Person> it is being resolved as a Repository<Person> now.

I encountered error 104 saying Repository wasn't pluggable for IRepository. This was because Repository was marked abstract. Making it non-abstract fixed that error and it is working as desired.

like image 106
Michael Shimmins Avatar answered Oct 20 '22 15:10

Michael Shimmins


I suggest you to take a look at the AddAllTypesOf method. I had some similar code and achieved my objectives by using it (and kept the auto register feature working).

In your case, you should just change

For<IRepository<Person>>().Use<Repository<Person>>(); For<IRepository<Product>>().Use<Repository<Product>>(); For<IRepository<Order>>().Use<Repository<Order>>(); For<IRepository<Whatever>>().Use<Repository<Whatever>>(); 

to

AddAllTypesOf(typeof(IRepository<>)); 

In the end, your container will be similar to:

return new Container(x =>         {             x.Scan(y =>             {                 y.TheCallingAssembly();                 y.AddAllTypesOf(typeof(IRepository<>));                 y.WithDefaultConventions();             });         }); 
like image 43
tyron Avatar answered Oct 20 '22 14:10

tyron