AttributeError when trying to use seek() to get last row of csv file

Question

I am trying to return the last row from a csv file. I am modifying another function that I wrote previously that returns the last line from a text file. It seemed to work as expected at first, but now when I call the function it throws an error.

reader.seek(0, os.SEEK_END)

AttributeError: '_csv.reader' object has no attribute 'seek'

---

import os
import csv
def getLastFile(filename):
    distance = 1024
    with open(filename,'rb') as f:
        reader = csv.reader(f)
        reader.seek(0, os.SEEK_END)
        if reader.tell() < distance:
            reader.seek(0, os.SEEK_SET)
            lines = reader.readlines()
            lastline = lines[-1]
        else:
            reader.seek(-1 * distance, os.SEEK_END)
            lines = reader.readlines()
            lastline = lines[-1]

    return lastline

Can someone please help me modify my code? I was pretty sure you could use seek in this way, maybe I'm mistaken?

Answer 1

Here's a slight variation of the core concept in the accepted answer to the question Have csv.reader tell when it is on the last line applied to your variation of the problem. Since each row is potentially a different length, there's really no way around having to read the whole file.

import csv

def get_last_row(csv_filename):
    with open(csv_filename, 'r') as f:
        lastrow = None
        for lastrow in csv.reader(f): pass
        return lastrow

Update

Here's a simpler and likely faster way to do it using a collections.deque. I got the idea from one of the answers to the question How to read an output line containing a list of integers produced.

from collections import deque
import csv

def get_last_row(csv_filename):
    with open(csv_filename, 'r') as f:
        try:
            lastrow = deque(csv.reader(f), 1)[0]
        except IndexError:  # empty file
            lastrow = None
        return lastrow