Is there a way in C++ to ensure that a virtual method in a subclass is in fact overriding a super class virtual method? Sometimes when I refactor, I forget a method and then wonder why it is not being called but I forgot to change the method signature so it is no longer overriding anything.
Thanks
Master C and Embedded C Programming- Learn as you goThe function overriding is the most common feature of C++. Basically function overriding means redefine a function which is present in the base class, also be defined in the derived class. So the function signatures are the same but the behavior will be different.
You don't need the override identifier to do this in C++, it simply enforces that you are doing it properly.
Function overriding is a concept in object-oriented programming which allows a function within a derived class to override a function in its base class, but with a different signature (and usually with a different implementation).
Function overriding is a redefinition of the base class function in its derived class with the same signature i.e. return type and parameters.
It is possible in C++11, with the override
identifier:
struct Base {
virtual void foo() const { std::cout << "Base::foo!\n"; }
};
struct Derived : virtual public Base {
virtual void foo() const override {std::cout << "Derived::foo!\n";}
};
This allows you to find out at compile time whether you are failing to override a method. Here, we neglect to make the method const
:
struct BadDerived : virtual public Base {
virtual void foo() override {std::cout << "BadDerived::foo!\n";} // FAIL! Compiler finds our mistake.
};
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