asyncio gather scheduling order guarantee

Question

Is it guaranteed that coroutines that are arguments to asyncio.gather will be scheduled with order preserved? Consider following example:

import asyncio

async def coro(i):
    print('{i} finished'.format(i=i))

async def main():
    await asyncio.gather(
            coro(0),
            coro(1),
            coro(2),
            coro(3),
            coro(4),
    )

loop = asyncio.get_event_loop()
loop.run_until_complete(main())

and the result:

0 finished
1 finished
2 finished
3 finished
4 finished

Answer 1

From Python documentation

awaitable asyncio.gather(*aws, loop=None, return_exceptions=False)

Run awaitable objects in the aws sequence concurrently.

If any awaitable in aws is a coroutine, it is automatically scheduled as a Task.

If all awaitables are completed successfully, the result is an aggregate list of returned values. The order of result values corresponds to the order of awaitables in aws.

So the order of result values is preserved, but the execution order is not.