I just saw someone use this piece of code:
ctx = canvas.getContext && canvas.getContext('2d');
How does the double ampersand work in this context? Would it not just assign "true" to the ctx variable?
In programming, a double ampersand is used to represent the Boolean AND operator such as in the C statement, if (x >= 100 && x >= 199). In HTML, the ampersand is used to code foreign letters and special characters such as the copyright and trademark symbols. See ampersand codes and address operator.
The logical OR ( || ) operator (logical disjunction) for a set of operands is true if and only if one or more of its operands is true. It is typically used with boolean (logical) values. When it is, it returns a Boolean value.
JavaScript uses the double ampersand ( && ) to represent the logical AND operator. The following expression uses the && operator: let result = a && b; Code language: JavaScript (javascript) If a can be converted to true , the && operator returns the b ; otherwise, it returns the a .
This is a common way to make sure your function exists before you call it.
It works like this (From developer.mozilla.com):
expr1 && expr2
Returnsexpr1
if it can be converted tofalse
; otherwise, returnsexpr2
. Thus, when used with Boolean values,&&
returnstrue
if both operands aretrue
; otherwise, returnsfalse
.
In other words, Javascript does not coerce the operands to boolean values unless it has to.
4 && 5
Returns 5, not true.
In your case, if the first expression is undefined
(which is convertible to false), then ctx
will be false, and the second expression does not get evaluated. If the first expression is a function (which cannot be converted to false
), then Javascript evaluates the second expression, and assigns it's value to the ctx
variable.
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