I have two classes:
class Outer {
    Inner inner = new Inner("value");
}
class Inner {
   private final String value;
   
   Inner(String value) {
      this.value = value;
   }
}
public Optional<Outer> getOptionalValue() {
   return Optional.of(new Outer());
} 
And my test:
public void testCLass() {
   Assertions.assertThat(getOptionalValue())
      .isPresent()
      .map(v -> v.inner.value)
      .isEqualTo("value");
}
   
I expect it to pass, because isPresent unwraps optional, map converts Outer into value and in the last method I just compare strings.
But it fails on the last line with the message:
Expecting:
 <Optional[value]>
to be equal to:
 <"value">
but was not.
I have no idea why the optional is not unwrapped
The javadoc for OptionalAssert's map method states
Call
mapon theOptionalunder test, assertions chained afterwards are performed on theOptionalresulting from themapcall.
However, isEqualTo is actually comparing the value of the AbstractAssert as a whole. It's not overriden for OptionalAssert to compare the enclosed value. An OptionalAssert's value, the Optional itself, is not equal to a String.
You'll want to use hasValue
Verifies that the actual
Optionalcontains the given value (alias ofcontains(Object)).Assertion will pass :
assertThat(Optional.of("something")).hasValue("something"); assertThat(Optional.of(10)).contains(10);
So
Assertions.assertThat(getOptionalValue())
      .isPresent()
      .map(v -> v.inner.value)
      .hasValue("value");
Or, because hasValue actually performs the isPresent check internally, you could just use
Assertions.assertThat(getOptionalValue())
      .map(v -> v.inner.value)
      .hasValue("value");
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