Menu
I'm working on setting up a shared content (navigation) for an asp.net MVC layout page.
Here is my partial view "_LayoutPartial.cshtml" with code to pull navigation data from a model.
@model MyApp.Models.ViewModel.LayoutViewModel
<p>
@foreach (var item in Model.navHeader)
{
//Test dump of navigation data
@Html.Encode(item.Name);
@Html.Encode(item.URL);
}
</p>
Here is how the code for my controller "LayoutController.cs" looks like.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using MyApp.Models.ViewModel;
namespace MyApp.Controllers
{
public class LayoutController : Controller
{
//
// GET: /Layout/
LayoutViewModel layout = new LayoutViewModel();
public ActionResult Index()
{
return View(layout);
}
}
}
Here is the code for the "_Layout.cshtml" page. I'm attempting to call the partial view here using Html.RenderAction(Action,Controller) method.
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
</head>
<body>
<p>
@{Html.RenderAction("Index","Layout");}
</p>
@RenderBody()
</body>
</html>
When the layout page executes the @{Html.RenderAction("Index","Layout");} line, it throws out an error message "Error executing child request for handler 'System.Web.Mvc.HttpHandlerUtil+ServerExecuteHttpHandlerAsyncWrapper'."
What am I missing friends? How can I call a partial view in a layout page?
Thank you all in advance!
802
Yes, even in Partial View also we can set Layout property which turns Partial View as normal View with Layout .
in mvc core You need to use ViewComponent instead partial view. create folder with the name "Component" and add class same MegaMenuViewComponent . The class must inherit from the ViewComponent.
To create a partial view, right-click on view -> shared folder and select Add -> View option. In this way we can add a partial view. It is not mandatory to create a partial view in a shared folder but a partial view is mostly used as a reusable component, it is a good practice to put it in the "shared" folder.
Instead of:
public ActionResult Index()
{
return View(layout);
}
do:
public ActionResult Index()
{
return PartialView(layout);
}
If you don't do that when you return a normal view from your child action, this normal view attempts to include the Layout, which in turn attempts to render the child action, which in turn returns a view, which in turn includes the Layout, which in turn attempts to render the child action, ... and we end up with names like the one ported by this very same site.
Also in your partial you don't need to do double encoding. The @ Razor function already does HTML encode:
@model MyApp.Models.ViewModel.LayoutViewModel
<p>
@foreach (var item in Model.navHeader)
{
@item.Name
@item.URL
}
</p>
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
