Ascending and Descending Number Order in java

Question

I'm doing an ascending and descending order number in java and here's my code:

System.out.print("Enter How Many Inputs: ");
int num1 = Integer.parseInt(in.readLine());
int arr[] = new int[num1];

for (int i = 0; i<num1; i++) {
    System.out.print("Enter Value #" + (i + 1) + ":");
    arr[i] =Integer.parseInt(in.readLine());
}

System.out.print("Numbers in Ascending Order:" );

for(int i = 0; i < arr.length; i++) {
    Arrays.sort(arr);
    System.out.print( " " +arr[i]);
}

System.out.println(" ");
System.out.print("Numbers in Descending Order: " );

Currently, the code generates the following:

Enter How Many Inputs: 5
Enter Value #1:3
Enter Value #2:5
Enter Value #3:6
Enter Value #4:11
Enter Value #5:2
Numbers in Ascending Order: 2 3 5 6 11 
Numbers in Descending Order: 

So, the Arrays.sort(arr) call seems to work - but I'm looking for a similarly simple way to provide the descending sort, and can't find it in the documentation. Any ideas?

Answer 1

Three possible solutions come to my mind:

1. Reverse the order:

//convert the arr to list first
Collections.reverse(listWithNumbers);
System.out.print("Numbers in Descending Order: " + listWithNumbers);

2. Iterate backwards and print it:

Arrays.sort(arr);
System.out.print("Numbers in Descending Order: " );
for(int i = arr.length - 1; i >= 0; i--){
  System.out.print( " " +arr[i]);
}

3. Sort it with "oposite" comparator:

Arrays.sort(arr, new Comparator<Integer>(){
   int compare(Integer i1, Integer i2) {
      return i2 - i1;
   }
});
// or Collections.reverseOrder(), could be used instead
System.out.print("Numbers in Descending Order: " );
for(int i = 0; i < arr.length; i++){
  System.out.print( " " +arr[i]);
}

Answer 2

public static void main(String[] args) {
          Scanner input =new Scanner(System.in);
          System.out.print("enter how many:");
         int num =input.nextInt();
    int[] arr= new int [num];
    for(int b=0;b<arr.length;b++){
   System.out.print("enter no." + (b+1) +"=");
   arr[b]=input.nextInt();
    }

    for (int i=0; i<arr.length;i++) {
        for (int k=i;k<arr.length;k++) {

        if(arr[i] > arr[k]) {

        int temp=arr[k];
        arr[k]=arr[i];
        arr[i]=temp;
        }
            }

    }
    System.out.println("******************\n output\t accending order");


    for (int i : arr){
        System.out.println(i);
    }
}
}