A friend asked me the Ruby best and performant way to achieve the effect of JavaScript's splice
method in Ruby.
This means no iteration on the Array itself or copies.
"begin at index start, remove length items and (optionally) insert elements. Finally return the removed items in an array." << This is misleading, see the JS example below.
http://www.mennovanslooten.nl/blog/post/41
Quick hack that doesn't have the optional substitution:
from_index = 2
for_elements = 2
sostitute_with = :test
initial_array = [:a, :c, :h, :g, :t, :m]
# expected result: [:a, :c, :test, :t, :m]
initial_array[0..from_index-1] + [sostitute_with] + initial_array[from_index + for_elements..-1]
What's yours? One line is better.
Update:
// JavaScript
var a = ['a', 'c', 'h', 'g', 't', 'm'];
var b = a.splice(2, 2, 'test');
> b is now ["h", "g"]
> a is now ["a", "c", "test", "t", "m"]
I need the resulting 'a' Array, not 'b'.
Use Array#[]=
.
a = [1, 2, 3, 4, 5, 6]
a[2..4] = [:foo, :bar, :baz, :wibble]
a # => [1, 2, :foo, :bar, :baz, :wibble, 6]
# It also supports start/length instead of a range:
a[0, 3] = [:a, :b]
a # => [:a, :b, :bar, :baz, :wibble, 6]
As for returning the removed elements, []=
doesn't do that... You could write your own helper method to do it:
class Array
def splice(start, len, *replace)
ret = self[start, len]
self[start, len] = replace
ret
end
end
First use slice!
to extract the part you want to delete:
a = [1, 2, 3, 4]
ret = a.slice!(2,2)
That leaves [1,2]
in a
and [3,4]
in ret
. Then a simple []=
to insert the new values:
a[2,0] = [:pancakes]
The result is [3,4]
in ret
and [1, 2, :pancakes]
in a
. Generalizing:
def splice(a, start, len, replacements = nil)
r = a.slice!(start, len)
a[start, 0] = replacements if(replacements)
r
end
You could also use *replacements
if you want variadic behavior:
def splice(a, start, len, *replacements)
r = a.slice!(start, len)
a[start, 0] = replacements if(replacements)
r
end
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