Array.includes() to find object in array

Question

I'm attempting to find an object in an array using Array.prototype.includes. Is this possible? I realize there is a difference between shallow and deep comparison. Is that the reason the below code returns false? I could not find a relevant answer for Array.includes().

Answer 1

Array.includes compares by object identity just like obj === obj2, so sadly this doesn't work unless the two items are references to the same object. You can often use Array.prototype.some() instead which takes a function:

const arr = [{a: 'b'}]  console.log(arr.some(item => item.a === 'b'))

But of course you then need to write a small function that defines what you mean by equality.

Answer 2

Its' because both of the objects are not the same. Both are stored at different place in memory and the equality operation results false.

But if you search for the same object, then it will return true.

Also, have a look at the below code, where you can understand that two identical objects also results false with the === operator.

For two objects to return true in ===, they should be pointing to same memory location.