hash = { "d" => [11, 22], "f" => [33, 44, 55] } # case 1 hash.map {|k,vs| vs.map {|v| "#{k}:#{v}"}}.join(",") => "d:11,d:22,f:33,f:44,f:55" # case 2 hash.map {|k,vs| vs.each {|v| "#{k}:#{v}"}}.join(",") => "11,22,33,44,55"
only difference is case 1 uses vs.map
, case 2 uses vs.each
.
What happened here?
Array#each
executes the given block for each element of the array, then returns the array itself.
Array#map
also executes the given block for each element of the array, but returns a new array whose values are the return values of each iteration of the block.
Example: assume you have an array defined thusly:
arr = ["tokyo", "london", "rio"]
Then try executing each
:
arr.each { |element| element.capitalize } # => ["tokyo", "london", "rio"]
Note the return value is simply the same array. The code inside the each
block gets executed, but the calculated values are not returned; and as the code has no side effects, this example performs no useful work.
In contrast, calling the array's map
method returns a new array whose elements are the return values of each round of executing the map
block:
arr.map { |element| element.capitalize } # => ["Tokyo", "London", "Rio"]
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