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I just want a quick way to create an array (or vector) of doubles that doesn't come out as type NumericRange.
Ive tried
val ys = Array(9. to 1. by -1.)
But this returns type Array[scala.collection.immutable.NumericRange[Double]]
Is there a way to coerce this to regular type Array[Double]?
748
Create Array with RangeUse of range() method to generate an array containing a sequence of increasing integers in a given range. You can use final argument as step to create the sequence; if you do not use final argument, then step would be assumed as 1.
The Scala List class holds a sequenced, linear list of items. Following are the point of difference between lists and array in Scala: Lists are immutable whereas arrays are mutable in Scala. Lists represents a linked list whereas arrays are flat.
scala> (9d to 1d by -1d).toArray
res0: Array[Double] = Array(9.0, 8.0, 7.0, 6.0, 5.0, 4.0, 3.0, 2.0, 1.0)
I think it slightly more concise and readable:
Array(9d to 1 by -1 : _*)
res0: Array[Double] = Array(9.0, 8.0, 7.0, 6.0, 5.0, 4.0, 3.0, 2.0, 1.0)
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