Arrange given numbers in ascending order

Question

I've just started learning C, and today I was given a question in which one of the parts was to accept the array of numbers from user and arrange them in ascending order. The array size was also to be specified by user. I used the following code for this purpose->

   for (i = 0; i <= y - 1; ++i) {
        for (ii = i + 1; ii <= y - 1; ++ii) {
            if (x[i] > x[ii]) {
                temp = x[i];
                x[i] = x[ii];
                x[ii] = temp;
            }
        }
    }
    int k;
    printf("\nNumbers arranged in ascending order:\n");
    for (k = 0; k < y; ++k) {
        printf("%d\n", x[i]);
    }

Here, variable y is the size of array, x is name of array variable (So the variable defining goes like this-> int x[y]; But the problem is, it just prints out the final value of array. To elaborate problem: Suppose I entered 3 as my array size. Then program asks me for 3 numbers which I chose 34,45,22. Now after this whole code is executed, it displays x[3] (now x[3] doesn't even exist! Since x[2] is final value in array. So it gives me memory location of variable.) Where am I going wrong?

Answer 1

You need to change

 printf("%d\n", x[i]);

to

printf("%d\n", x[k]);

in the printing loop as you're using k as the loop counter variable.