Argument type auto deduction and anonymous lambda functions

Question

Lets say I have these lines of code;

std::vector<int> ints; std::for_each(ints.begin(), ints.end(), [](int& val){ val = 7; }); 

However, I dont want to specify the argument type in my lambda functions, ie, I want to write something like this;

std::for_each(ints.begin(), ints.end(), [](auto& val){ val = 7; }); 

Is there anyway this can be achieved?

(boost::lambda doesn't need types to be specified...)

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Update:

For now I use a macro: #define _A(container) decltype(*std::begin(container)) so I can do:

std::for_each(ints.begin(), ints.end(), [](_A(ints)& val){ val = 7; }); 

Answer 1

No. "Polymorphic lambdas" is what this feature was referred to during the C++ committee discussions, and it was not standardized. The parameter types of a lambda must be specified.

You can use decltype though:

std::for_each(ints.begin(), ints.end(), [](decltype(*ints.begin())& val){ val = 7; });