argparse argument order

Question

I have a little problem.

I use argparse to parse my arguments, and it's working very well.

To have the args, I do :

p_args = parser.parse_args(argv) args = dict(p_args._get_kwargs()) 

But the problem with p_args is that I don't know how to get these arguments ordered by their position in the command line, because it's a dict.

So is there any possibility to have the arguments in a tuple/list/ordered dict by their order in the command line?

Answer 1

To keep arguments ordered, I use a custom action like this:

import argparse class CustomAction(argparse.Action):     def __call__(self, parser, namespace, values, option_string=None):         if not 'ordered_args' in namespace:             setattr(namespace, 'ordered_args', [])         previous = namespace.ordered_args         previous.append((self.dest, values))         setattr(namespace, 'ordered_args', previous) parser = argparse.ArgumentParser() parser.add_argument('--test1', action=CustomAction) parser.add_argument('--test2', action=CustomAction) 

To use it, for example:

>>> parser.parse_args(['--test2', '2', '--test1', '1']) Namespace(ordered_args=[('test2', '2'), ('test1', '1')], test1=None, test2=None)