This MSDN reference seems to indicate that when an int?
(or any Nullable<T>
) has a value, it's always boxed (and hence a much less efficient store of data, memory-wise than an int
). Is that the case?
That page refers to when you are boxing the Nullable<T>
struct, not the values inside the struct itself.
There is no boxing involved in storing a nullable type until you try boxing the nullable itself:
int? a = 42; // no boxing
int? n = null; // no boxing
object nObj = n; // no boxing
object aObj = a; // only now will boxing occur
This behavior is no different than when boxing a regular value type (with the exception of handling the null case) so it is really to be expected.
No. The Nullable object is a generic struct, and internally handles the value of T without boxing.
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