The following code
(let [coll [1 2 3 4 5]
filters [#(> % 1) #(< % 5)]]
(->> coll
(filter (first filters))
(filter (second filters))))
Gives me
(2 3 4)
Which is great, but how do I apply all the filters in coll without having to explicitly name them?
There may be totally better ways of doing this, but ideally I'd like to know an expression that can replace (filter (first filters)) (filter (second filters)) above.
Thanks!
Clojure 1.3 has a new every-pred
function, which you could use thusly:
(filter (apply every-pred filters) coll)
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