Appengine filter inequality and ordering fails

Question

I think I'm overlooking something simple here, I can't imagine this is impossible to do.

I want to filter by a datetime attribute and then order the result by a ranking integer attribute. When I try to do this:

query.filter("submitted >=" thisweek).order("ranking") 

I get the following:

BadArgumentError: First ordering property must be the same as inequality filter property, if specified for this query; received ranking, expected submitted 

Huh? What am I missing?

Thanks.

Answer 1

The datastore isn't capable of ordering a query that contains an inequality by any property other than the one used in the inequality.

This can often be worked around by adding a property that can be filtered with an equality; in this case, it may be possible to have a BooleanProperty tracking whether an entity is from the current week, and update it for all entities at the end of each week.

Answer 2

I used another trick, which worked out simply because of the format I needed my data in (a list of dicts). In this case I run the datetime-based query, create dicts from the returned ents, and then sort by the numeric 'counter' property. Reversing the sort gave me a descending order. Keep in mind I only requested 10 results, on a fairly small datastore.

q = food.Food.all() q.filter("last_modified <=", now) q.filter("last_modified >=", hour_ago)  ents = q.fetch(10)  if ents:   results = [{     "name": ent.name,     "counter": ent.counter     } for ent in ents]    # reverse list for 'descending' order   results.sort(reverse=True) 

Example result:

[{'counter': 111L, 'name': u'wasabi'}, {'counter': 51L, 'name': u'honeydew'}, {'counter': 43L, 'name': u'mars bar'}, {'counter': 37L, 'name': u'scallop'}, {'counter': 33L, 'name': u'turnip'}, {'counter': 29L, 'name': u'cornbread'}, {'counter': 16L, 'name': u'mackerel'}, {'counter': 10L, 'name': u'instant coffee'}, {'counter': 3L, 'name': u'brussel sprouts'}, {'counter': 2L, 'name': u'anchovies'}]