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Antlr Extraneous Input

Tags:

java

antlr

antlr4

I have a grammar file BoardFile.g4 that has (relevant parts only):

grammar Board;

//Tokens
GADGET : 'squareBumper' | 'circleBumper' | 'triangleBumper' | 'leftFlipper' | 'rightFlipper' | 'absorber' | 'portal' ;
NAME : [A-Za-z_][A-Za-z_0-9]* ;
INT : [0-9]+ ;
FLOAT : '-'?[0-9]+('.'[0-9]+)? ;
COMMENT : '#' ~( '\r' | '\n' )*;
WHITESPACE : [ \t\r\n]+ -> skip ;
KEY : [a-z] | [0-9] | 'shift' | 'ctrl' | 'alt' | 'meta' | 'space' | 'left' | 'right' | 'up' | 'down' | 'minus' | 'equals' | 'backspace' | 'openbracket' | 'closebracket' | 'backslash' | 'semicolon' | 'quote' | 'enter' | 'comma' | 'period' | 'slash' ;
KEYPRESS : 'keyup' | 'keydown' ;

//Rules
file : define+ EOF ;
define : board | ball | gadget | fire | COMMENT | key ;
board : 'board' 'name' '=' name ('gravity' '=' gravity)? ('friction1' '=' friction1)? ('friction2' '=' friction2)? ;
ball : 'ball' 'name' '=' name 'x' '=' xfloat 'y' '=' yfloat 'xVelocity' '=' xvel 'yVelocity' '=' yvel ;
gadget : gadgettype 'name' '=' name 'x' '=' xint 'y' '=' yint ('width' '=' width 'height' '=' height)? ('orientation' '=' orientation)? ('otherBoard' '=' name 'otherPortal' '=' name)? ;
fire : 'fire' 'trigger' '=' trigger 'action' '=' action ;
key : keytype 'key' '=' KEY 'action' '=' name ;

name : NAME ;
gadgettype : GADGET ;
keytype : KEYPRESS ;
gravity : FLOAT ;
friction1 : FLOAT ;
friction2 : FLOAT ;
trigger : NAME ;
action : NAME ;
yfloat : FLOAT ;
xfloat : FLOAT ;
yint : INT ;
xint : INT ;
xvel : FLOAT ;
yvel : FLOAT ;
orientation : INT ;
width : INT ;
height : INT ;

This generates the lexer and parser fine. However, when I use it against the following file, it gives the following error:

line 12:0 extraneous input 'keyup' expecting {<EOF>, KEYPRESS}

File to Parse:

board name=keysBoard gravity=5.0 friction1=0.0 friction2=0.0

# define a ball
ball name=Ball x=0.5 y=0.5 xVelocity=2.5 yVelocity=2.5

# add some flippers
leftFlipper name=FlipL1 x=16 y=2 orientation=0
leftFlipper name=FlipL2 x=16 y=9 orientation=0

# add keys. lots of keys.
keyup key=space action=apple
keydown key=a action=ball
keyup key=backslash action=cat
keydown key=period action=dog

I went through other questions about this error in SO but none helped me. I cannot figure out what's going wrong. Why am I getting this error?

like image 415
tripatheea Avatar asked May 13 '14 01:05

tripatheea


1 Answers

The string "keyup" is being tokenized as a NAME token: that is the problem.

You must realize that the lexer operates independently from the parser. If the parser is trying to match a KEYPRESS token, the lexer does not "listen" to it, but just constructs a token following the rules:

  1. match the rule that consumes the most characters
  2. if there are more rules that match the same amount of characters, choose the one that is defined first

Taking these rules into account, and the order of your rules:

NAME : [A-Za-z_][A-Za-z_0-9]* ;

INT : [0-9]+ ;

KEY : [a-z] | [0-9] | 'shift' | 'ctrl' | 'alt' | 'meta' | 'space' | 'left' | 'right' | 'up' | 'down' | 'minus' | 'equals' | 'backspace' | 'openbracket' | 'closebracket' | 'backslash' | 'semicolon' | 'quote' | 'enter' | 'comma' | 'period' | 'slash' ;

KEYPRESS : 'keyup' | 'keydown' ;

a NAME token will be created before most of the KEY alternatives, and all of the KEYPRESS alternatives will be created.

And since an INT matches one or more digits and is defined before KEY which also has a single digit alternative, it is clear that the lexer will never produce a KEY or KEYPRESS token.

If you move the NAME and INT rule below the KEY and KEYPRESS rules, then most of the tokens will be constructed as you expect, is my guess.

EDIT

A possible solution would look like:

KEY : [a-z] | 'shift' | 'ctrl' | 'alt' | 'meta' | 'space' | 'left' | 'right' | 'up' | 'down' | 'minus' | 'equals' | 'backspace' | 'openbracket' | 'closebracket' | 'backslash' | 'semicolon' | 'quote' | 'enter' | 'comma' | 'period' | 'slash' ;

KEYPRESS : 'keyup' | 'keydown' ;

NAME : [A-Za-z_][A-Za-z_0-9]* ;

SINGLE_DIGIT : [0-9] ;

INT : [0-9]+ ;

I.e. I removed the [0-9] alternative from KEY and introduced a SINGLE_DIGIT rule (which is placed before the INT rule!).

Now create some extra parser rules:

integer : INT | SINGLE_DIGIT ;

key : KEY | SINGLE_DIGIT ;

and change all occurrences of INT inside parser rules to integer (don't call your rule int: it is a reserved word) and change all KEY to key.

And you might also want to do something similar to NAME and the [a-z] alternative in KEY (i.e. a single lowercase char would now never be tokenized as a NAME, always as a KEY).

like image 165
Bart Kiers Avatar answered Nov 01 '22 18:11

Bart Kiers