I'd like to remove an item from a list, based on another list.
"my_list_one": [
"item1",
"item2",
"item3"
]
My second list:
"my_list_two": [
"item3"
]
How do I remove 'item3' from this list, to set a new fact?
I tried using '-' and union, but this does not end in the desired end result.
set_fact:
my_list_one: "{{ my_list_one | union(my_list_two) }}"
End goal:
"my_list_one": [
"item1",
"item2"
]
Use difference
not union
:
{{ my_list_one | difference(my_list_two) }}
An example playbook (note that you must also provide variable name to set_fact
):
---
- hosts: localhost
connection: local
vars:
my_list_one:
- item1
- item2
- item3
my_list_two:
- item3
tasks:
- set_fact:
my_list_one: "{{ my_list_one | difference(my_list_two) }}"
- debug: var=my_list_one
The result (excerpt):
TASK [debug] *******************************************************************
ok: [localhost] => {
"my_list_one": [
"item1",
"item2"
]
}
Ansible - Set Theory Filters
To get the difference of 2 lists (items in 1 that don’t exist in 2):
{{ list1 | difference(list2) }}
Note: Order matters, so you want {{ my_list_one | difference(my_list_two) }}
Since it's just a Jinja2 template, in pure Python, list - list
is not defined.
In [1]: list1 = [1, 2, 3]
In [2]: list2 = [3]
In [3]: list1 - list2
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-3-a683b4e3266d> in <module>()
----> 1 list1 - list2
TypeError: unsupported operand type(s) for -: 'list' and 'list'
Instead, you can do list-comprehension
In [5]: [i for i in list1 if i not in list2]
Out[5]: [1, 2]
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