In terms of memory consumption, are these equivalent or do we get a new function instance for every object in the latter?
var f=function(){alert(this.animal);}
var items=[];
for(var i=0;i<10;++i)
{
var item={"animal":"monkey"};
item.alertAnimal=f;
items.push(item);
}
and
var items=[];
for(var i=0;i<10;++i)
{
var item={"animal":"monkey"};
item.alertAnimal=function(){alert(this.animal);};
items.push(item);
}
EDIT
I'm thinking that in order for closure to work correctly, the second instance would indeed create a new function each pass. Is this correct?
The advantage of an anonymous function is that it does not have to be stored in a separate file. This can greatly simplify programs, as often calculations are very simple and the use of anonymous functions reduces the number of code files necessary for a program.
Anonymous functions are often arguments being passed to higher-order functions, or used for constructing the result of a higher-order function that needs to return a function. If the function is only used once, or a limited number of times, an anonymous function may be syntactically lighter than using a named function.
One of the more famous use cases for anonymous functions are Immediately Invokable Function Expressions (IIFE). IIFE, for short, is a pattern that uses an anonymous function which immediately creates and invokes the contents of the function. // IIFE (Immediately Invokable Function Expression) (function() { console.
You should pefer the first method, since the second one creates a function every time the interpreter passes that line.
Regarding your edit: We are in the same scope all the time, since JavaScript has function scope instead of block scope, so this might be optimizable, but i did not encounter an implementation that doesn't create it every time. I would recommend not to rely on this (probably possible) optimization, since implementations that lack support could likely exceed memory limits if you use this technique extensively (which is bad, since you do not know what implementation will run it, right?).
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