Anonymous class replaced with lambda expressions

Question

I have sample code which uses Java 8 new stream functionality (get a range of int values 1 .. 20, skip the first 9, then take remaining 10, each int value: reduce by one and multiply by 2).

System.out.println(Arrays.toString(     IntStream.rangeClosed(1, 20).skip(9).limit(10).map((new IntUnaryOperator() {         @Override         public int applyAsInt(int operand) {             return operand - 1;         }     }).andThen(new IntUnaryOperator() {         @Override         public int applyAsInt(int operand) {             return operand * 2;         }     })).toArray())); 

The output is as follows:

[18, 20, 22, 24, 26, 28, 30, 32, 34, 36] 

Now I want to replace anonymous classes with Lambda expressions. The following conversion works fine (the second anonymous class replaced with i -> i * 2 lambda expression) and I get the same output:

System.out.println(Arrays.toString(     IntStream.rangeClosed(1, 20).skip(9).limit(10).map((new IntUnaryOperator() {         @Override         public int applyAsInt(int operand) {             return operand - 1;         }     }).andThen(i -> i * 2)).toArray())); 

However, when I replace the first anonymous class with lambda expression:

System.out.println(     Arrays.toString(         IntStream.rangeClosed(1, 20).skip(9).limit(10)             .map((v -> v - 1).andThen(i -> i * 2)).toArray())); 

I am not able to compile my code. The error says Operator '-' cannot be applied to '<lambda parameter>', 'int'

Do you know how to combine two lambda expressions with IntUnaryOperator.andThen?

I know I could use ... .limit(10).map(v -> v - 1).map(i -> i * 2).toArray() ... which works fine but I would like to find out how to use IntUnaryOperator.andThen with lambdas (if that possible).

Answer 1

You have to explicitly cast the first lambda expression to IntUnaryOperator. The following code works:

System.out.println(         Arrays.toString(                 IntStream.rangeClosed(1, 20).skip(9).limit(10)                         .map(((IntUnaryOperator) v -> v - 1).andThen(i -> i * 2)).toArray()));