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Angular UI-Router sending root url to 404

I am having an infuriating issue regarding ui-router. Everything works as I want, where all bad URLs are sent to the 404 state. However, even though my default state is correctly rendered when the url is /#/, the url of / is redirected to /404/. How can I server the default state to both / and /#/?

app.js

MyApp.config( function ($stateProvider, $urlRouterProvider) {

// For any unmatched url, send to 404
$urlRouterProvider.otherwise("/404/");

$stateProvider
    // Home  (default)
    .state('default', {
        url: '/',
        resolve: {
            ...
        },
   }
});
like image 232
Darwin Tech Avatar asked May 02 '14 23:05

Darwin Tech


2 Answers

I think this will accomplish your needs -

MyApp.config(function($stateProvider, $urlRouterProvider) {
    // the known route
    $urlRouterProvider.when('', '/');

    // For any unmatched url, send to 404
    $urlRouterProvider.otherwise('/404');

    $stateProvider
        // Home  (default)
        .state('default', {
            url: '/',
            resolve: {
                // ...
            }
            // ....
        });
});

I refered to this post. You may need to use a regular expression to handle routes with data.

Instead of the # in your URL you can use a query string too and grab it via $stateParams in a state.

Here is how you can do that -

  // ....

  $stateProvider

    .state('default', {
        url: '/?data',
        templateUrl: 'templates/index.html',
        controller: 'defaultCtrl'
    })

And then you can use this below to go to home with data -

var toStateData = {
    key1: 'value1',
    key2: 'value2'
}

$state.go('default', {data: JSON.stringify(toStateData)});

You don't have to stringify the data in $stateParams but this will allow more options with one parameter. In the defaultCtrl controller you can get the passed query string like this -

var stateData = JSON.parse($stateParams.data);
var key1 = stateData.key1;
// ....
like image 65
Ross Avatar answered Oct 12 '22 13:10

Ross


I wanted to do this only with states, so no url provider involved. I found the following solution which I think is good:

(sorry it's coffeescript)

  $stateProvider.
    state('base.public.notFound',
      url:         '^*path'
      templateUrl: 'views/layouts/404.html'
    )

Put this as the last state and you are done!

like image 37
Francesco Belladonna Avatar answered Oct 12 '22 13:10

Francesco Belladonna