I'm displaying a list of thumbnails with this code:
<div class ="channel" ng-repeat ="channel in UIModel.channels" ng-class ="{evenchannel: ($index % 2) == 0, oddchannel: ($index % 2) == 1}">
<img class="channel-img" ng-src ="data/channels/{{$index + 1}}/thumb"/>
</div>
In the controller I have an ajax request which grabs new thumbnail images. Angular thus updates the images but causes flickering. Is there a way to double buffer or not have the list deleted in the process of updating the DOM?
To go along with @cexbrayat's answer, if you don't have any IDs you can also just associated it and track by $index
. Which is an internal iteration # during an ng-repeat.
<div ng-repeat="channel in UIModel.channels track by $index"></div>
You can use track by
in your ng-repeat
with a unique identifier. If I suppose your channel object has an id, you can do :
<div class ="channel" ng-repeat="channel in UIModel.channels track by channel.id"></div>
The tracking avoids the complete DOM deletion and recreation at every updates, as Angular will be able to track if the element is the same as previously and will keep the DOM element.
Try the answers from @Mark Pieszak and @cexbrayat first, however if you are using ngAnimate
in your application, they may not completely solve your problem.
In addition to:
<div class="channel" ng-repeat="channel in UIModel.channels track by channel.id"></div>
I needed to add the following CSS to disable animation for this ng-repeat
:
.channel .ng-leave, .channel .ng-leave-active {
display: none !important;
}
.channel .ng-move, .channel .ng-move-active {
display: none !important;
}
This ensures that once the animation starts, the item is immediately hidden. The alternatives are to actually use an animation, or to disable the animation on the element in code with $animate.enabled('div.channel', false);
.
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