android.provider.Settings.Secure.ANDROID_ID returns "android_id"

Question

Is there reason android.provider.Settings.Secure.ANDROID_ID is return the constant "android_id" instead of a 64-bit number as a hex string ?

Description : android.provider.Settings.Secure.ANDROID_ID

• A 64-bit number (as a hex string) that is randomly generated when the user first sets up the device and should remain constant for the lifetime of the user's device. The value may change if a factory reset is performed on the device.

I am using a Samsung Galaxy S4 w /

 <uses-sdk android:minSdkVersion="13"  android:targetSdkVersion="19" />

Cheers

Answer 1

The android.provider.Settings.Secure.ANDROID_ID is a constant that can be used in android.provider.Settings.Secure.getString(ContentResolver resolver, String name). By default it is set to 'android_id' since that's the name of the property containing the actual Android ID.

Use this code to get the actual id:

String androidId = Secure.getString(getContext().getContentResolver(), Secure.ANDROID_ID); 

Answer 2

android.provider.Settings.Secure.ANDROID_ID is to big so use this answer from: https://stackoverflow.com/a/10151694/1815624

new BigInteger(string, 16).longValue()

For any value of someLong:

new BigInteger(Long.toHexString(someLong), 16).longValue() == someLong

In other words, this will return the long you sent into Long.toHexString() for any long value, including negative numbers. It will also accept strings that are bigger than a long and silently return the lower 64 bits of the string as a long. You can just check the string length <= 16 (after trimming whitespace) if you need to be sure the input fits in a long.

https://stackoverflow.com/a/10151694/1815624