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android.database.sqlite.SQLiteConstraintException: error code 19: constraint failedexception

I created a table named resources but when I insert values in it, this exception is thrown:

android.database.sqlite.SQLiteConstraintException:
error code 19: constraint failedexception

Here is my create table statement:

public static final String DATABASE_CREATE = 
    "CREATE TABLE " + table_resources + "(ID INTEGER PRIMARY KEY, 
    KEY_TYPE text, KEY_ENCODING text, KEY_WIDTH text, KEY_HEIGHT text, 
    KEY_DATA text, KeyIId text)";

The following is my insert code:

JSONObject show = data.getJSONObject(i);
if (show.get("type").equals("resource_updates")) {
    JSONArray resources = show.getJSONArray("resources");
    try {
        System.out.println("length of resources is is " + resources.length());
        for (int resourceIndex = 0; resourceIndex < resources.length(); resourceIndex++) {
            type = resources.getJSONObject(resourceIndex).getString("type").toString();
            encoding = resources.getJSONObject(resourceIndex).getString("encoding").toString();
            data1 = resources.getJSONObject(resourceIndex).getString("data").toString();
            id = resources.getJSONObject(resourceIndex).getString("id").toString();
            try {
                width = resources.getJSONObject(resourceIndex).getString("width").toString();
            } catch (Exception e) {
                System.out.println(e);
                width = "null";
            }
            try {
                height = resources.getJSONObject(resourceIndex).getString("height").toString();
            } catch (Exception e) {
                e.printStackTrace();
                height = "null";
            }
            db.insert(type,encoding,width,height, data1,iid);
        }
    } catch (Exception e) {
        e.printStackTrace();
        System.out.println(e + "exception");
        System.out.println("exception in  the resources");
    }
}

Can anyone tell me where could be the problem?

like image 741
ekjyot Avatar asked Nov 14 '11 05:11

ekjyot


1 Answers

Constraint failed usually indicates that you did something like pass a null value into a column that you declare as not null when you create your table.

like image 169
skynet Avatar answered Sep 28 '22 01:09

skynet