Android Toggle Button in ActionBar

Question

Is there a way to put a ToggleButton in the ActionBar and get it to save what state it is in, so when you open the same activity again it is in the same state as you left it?

Extra: If possible have android 2.3.3 - 2.3.7 backward compatibility

Answer 1

First define a layout that contains your Toggle:

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
  android:layout_width="fill_parent"
  android:layout_height="wrap_content">
  <ToggleButton
    android:id="@+id/actionbar_service_toggle"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:textOn="Logging On"
    android:textOff="Logging Off" />
</RelativeLayout>

Then you have two alternatives to proceed:

Using an action layoput:

<menu xmlns:android="http://schemas.android.com/apk/res/android" >
    <item
        android:id="@+id/myswitch"
        android:title=""
        android:showAsAction="always"
        android:actionLayout="@layout/actionbar_service_toggle" />   
</menu>

Inflating programmatically: In your Activity or Fragment you do:

ActionBar actionBar = getSupportActionBar();
actionBar.setCustomView(R.layout.actionbar_top);
actionBar.setDisplayOptions(ActionBar.DISPLAY_SHOW_HOME | ActionBar.DISPLAY_SHOW_CUSTOM);
...
ToggleButton button = (ToggleButton) findViewById(R.id.actionbar_service_toggle);