Android sleep() without blocking UI

Question

For my new Android application I need a function, that timeout my application for 3 Seconds. I tried the function "sleep()" like this:

seekBar1.setProgress(50);                // Set something for my SeekBar  try{    Thread.sleep(3000);                   // Wait for 3 Seconds } catch (Exception e){    System.out.println("Error: "+e);      // Catch the exception }  button.setEnabled(true);                 // Enable my button 

It seems to work, but if I was running the application it does it like this: Wait for 3 Seconds, set progress and enable button. I want first to set the progress and then wait for 3 seconds and only then to enable the button.

Is "sleep()" for the right for my use or what can I do else that my application does it in the right order?

Answer 1

You can use postDelayed() method like this:

handler=new Handler(); Runnable r=new Runnable() {     public void run() {         //what ever you do here will be done after 3 seconds delay.                   } }; handler.postDelayed(r, 3000); 

Answer 2

You shouldn't ever block the ui thread with a sleep. Its ok to sleep on another thread, but even then it should be avoided. The right way to do this is to post a Runnable to a Handler. Then put whatever code you want to run after the delay in the run() method of the Runnable.