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Android libgdx big screen resolution

Tags:

android

libgdx

How can I support (make an algorithm) for libgdx for supporting multiple screen resolution? I made my app work on HTC Tattoo using if statments with parameters like:

if (Gdx.input.getX()==40) {

What is a good algorithm for making this work on bigger screens? I tried this but without any result:

publis static int translatex() {
     float p = (float)Gdx.graphics.getHeight()*340;
     return (int) p*Gdx.input.getX();
}

340 is the base x (the x resolution on my phone) used by me on the HTC Tattoo. So.....how can I make a function for supporting big screens with absolute values. I don`t want to change the if-statements.

like image 303
Felix Avatar asked Dec 03 '22 08:12

Felix


1 Answers

It's pretty easy. You basically build your entire program for your native resolution, but in everything dealing with positioning and texture sizing have something like this:

private void resize()
{
    float x = Gdx.graphics.getWidth();
    float y = Gdx.graphics.getHeight();

    float changeX = x / assumeX; //being your screen size that you're developing with
    float changeY = y / assumeY;

    position = new Vector2(position.x * changeX, position.y * changeY);
    width = startWidth * changeX;
    height = startHeight * changeY;
    bounds = new Vector2 (position.x, (Gdx.graphics.getHeight() - position.y) - height);

}

Basically what you're doing is taking every object generated and running it through something that increases/decreases depending on the change in the x/y values in your resolution. The further it is from the native, the bigger it will be. When checking of something is somewhere or putting something somewhere, always code it as your desired resolution but run it through a resize function before displaying it or letting it interact with the rest of your program.

like image 75
Remm Avatar answered Dec 08 '22 00:12

Remm