In my Android app, I have a button with the background image of an Amazon.com product (let's say a shirt or something), and when clicked I would like it to open in the Amazon app (com.amazon.mShop.android) if is already installed rather than in the browser, and in the browser if the app is not installed.
I have been able to find how to add a deep link to a specific Amazon client app, but not how to link to a specific item that would open with open with the Amazon app.
Currently, my click listener opens in a browser by doing the following:
b3.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
Intent intent = new Intent();
intent.setAction(Intent.ACTION_VIEW);
intent.addCategory(Intent.CATEGORY_BROWSABLE);
intent.setData(Uri.parse(urlOfItemOnAmazonSite));
startActivity(intent);
}
})
The Amazon developer's home page is probably the best place for this answer. This may be a good start: https://developer.amazon.com/public/apis/earn/in-app-purchasing/docs/deeplink#Link%20Configuration. Here they explain how to construct the Uri
you'll need to use to set the Intent data.
Of course, you may want to be careful and wrap startActivity
in a try/catch in case Amazon isn't installed and it throws an ActivityNotFoundException
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