Android add ID to a layout

Question

How do I define an ID to a layout?

I am trying to add an ID to a linearlayout and setting an onclick listener:

XML:

<LinearLayout
   android:id="@+id/?????????"
   android:layout_width="match_parent"
   android:layout_height="match_parent"
   android:orientation="vertical"
   android:onClick="btnHandler" >
</LinearLayout>

Class:

public class MainActivity extends Activity {
    //....

    public void btnHandler(View v){
       switch(v)
       {
          case R.id.????? :
       }
    }
}

Answer 1

Since you have this

 <LinearLayout
 android:id="@+id/linearlayout"
 android:layout_width="match_parent"
 android:layout_height="match_parent"
 android:orientation="vertical"
 android:onClick="btnHandler" >
</LinearLayout>

You can do as below

  public void btnHandler(View v)
  {
      switch(v.getId()) // use v.getId()
   {
      case R.id.linearlayout :
      break;  // also don't forget the break;
   }

  }  

Edit:

If you have button then you can do as below.

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:id="@+id/linearlayout"
    android:onClick="clickEvent"
    android:orientation="vertical" >
<Button
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:id="@+id/bt1"
    android:text="button"   
    android:onClick="clickEvent"
    />

</LinearLayout>

Then in your activity

public void clickEvent(View v)
{
       switch(v.getId())
       {
          case R.id.linearlayout :
              Log.i("......"," linear layout clicked");
          break; 
          case R.id.bt1 :
        Log.i("......"," button clicked");
            break;
       }
}

Answer 2

Instead of

switch(v)

use

switch(v.getId())

and set your id from the xml

android:id="@+id/idValue"