If I launch Activity2 from Activity1 by this way: startActivity(Activity2);
what executes first: onStop()
(Activity1) or onStart()
(Activity2) ?
Do they work simultaneously or in turn? If one after another, what is first?
So in general : what is the activity's state order when first activity starts second, if this order exists?
An Android activity goes through six major lifecycle stages or callbacks. These are: onCreate() , onStart() , onResume() , onPause() , onStop() , and onDestroy() . The system invokes each of these callbacks as an activity enters a new state.
When the Activity finally gets rendered on the screen, onResume() method is invoked. At this point, the Activity is in the active state and is interacting with the user. If the activity loses its focus and is only partially visible to the user, it enters the paused state.
onCreate() You must implement this callback, which fires when the system first creates the activity. On activity creation, the activity enters the Created state.
when I have checked it by programmatically its following all steps and easy to understand
Let Say Activity A is starting Activity B by Calling StartActivity(Intent) method then lifecycle call be like this :-
Now Button click for startActivity(intent)
A onPause()
B onCreate()
B onStart()
B onResume()
A onStop()
..... If you press back button from Activity B then lifeCycle call will be .....
B onPause()
A onRestart()
A onStart()
A onResume()
Now one more scenario "From Activity A start Activity B by calling StartActivity(Intent) on button click and use finish() method inside onstart() method on Activity B"
A onPause()
B onCreate()
B onStart()
A onResume()
B onStop()
B onDestory()
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